AP Chemistrymediummcq1 pt
For PCl₅(g) ⇌ PCl₃(g) + Cl₂(g), how are Kp and Kc related at temperature T?
A.Kp equals Kc multiplied by RT
B.Kp equals Kc divided by RT
C.Kp equals Kc at every temperature
D.Kp equals Kc multiplied by RT squared
The general conversion is Kp = Kc(RT)^Δn, where Δn counts moles of gaseous products minus gaseous reactants. Decomposition of PCl₅ releases two moles of gas from one, so Δn = +1 here. The relation therefore reads Kp = Kc(RT). It follows directly from substituting PV = nRT into each partial-pressure term of the expression.
AKp equals Kc multiplied by RT
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