AP Chemistrymediummcq1 pt
For PbI₂(s) ⇌ Pb²⁺ + 2I⁻, what is Ksp in terms of molar solubility s?
A.4s³
B.s²
C.2s²
D.s³
Explanation
Core Concept
At saturation [Pb²⁺] = s and [I⁻] = 2s, so Ksp = s × (2s)² = 4s³. The coefficient 2 doubles the iodide concentration and squares it.
Correct Answer
A4s³
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