AP Calculus ABeasymcq1 pt

A particle's velocity is v(t)=4t+1v(t)=4t+1 m/s at time tt seconds. What is its acceleration?

A.4t+14t+1 m/s2^2
B.2t2+t2t^2+t m/s2^2
C.00 m/s2^2
D.44 m/s2^2

Explanation

Core Concept

Acceleration is the derivative of velocity, so a(t)=v(t)=4a(t)=v'(t)=4.

Correct Answer

D44 m/s2^2

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