AP Calculus ABeasymcq1 pt

A particle's velocity is v(t)=3t2+5v(t)=3t^2+5 m/s at time tt seconds. What is its acceleration function a(t)a(t)?

A.a(t)=3t2+5a(t)=3t^2+5 m/s2^2
B.a(t)=6t+5a(t)=6t+5 m/s2^2
C.a(t)=6ta(t)=6t m/s2^2
D.a(t)=t3+5ta(t)=t^3+5t m/s2^2

Explanation

Core Concept

Acceleration is the derivative of velocity. Differentiating gives v(t)=6tv'(t)=6t.

Correct Answer

Ca(t)=6ta(t)=6t m/s2^2

More Unit 4: Contextual Applications of Differentiation practice questions

Try a random question →

Practice more AP Calculus AB questions with full explanations

Practice Unit 4: Contextual Applications of Differentiation Questions →