Apentix/AP Calculus AB/Unit 4: Contextual Applications of Differentiation/Question

AP Calculus ABeasymcq1 pt

A particle's velocity is $v(t)=3t^2-12t+9$ m/s. What is its acceleration at $t=1$ second?

A.

-6

m/s

^2

B.

6

m/s

^2

C.

-12

m/s

^2

D.

0

m/s

^2

Explanation

Core Concept

Acceleration is $a(t)=v'(t)=6t-12$ . Substituting $t=1$ gives $6-12=-6$ m/s $^2$ .

Correct Answer

A $-6$ m/s $^2$

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