AP Calculus BCmediummcq1 pt
For x = 2t, y = t² + 1, the particle's speed at t = 1 is
A.2√2
B.2
C.√8/2
D.4
Explanation
Core Concept
|v| = √(4 + 4t²); at t = 1: √8 = 2√2.
Correct Answer
A2√2
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