AP Calculus ABeasymcq1 pt

A particle moves along a line with velocity v(t)=2t6v(t)=2t-6 m/s for t0t\geq 0. At what time does the particle change direction?

A.t=0t=0 s
B.t=3t=3 s
C.t=6t=6 s
D.t=3t=-3 s

Explanation

Core Concept

The particle changes direction when the velocity changes sign. Solving 2t6=02t-6=0 gives t=3t=3, and vv is negative before and positive after t=3t=3.

Correct Answer

Bt=3t=3 s

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