AP Calculus ABeasymcq1 pt

A particle moves along a line with position s(t)=t2+1s(t)=t^2+1, where tt is in seconds and ss is in meters. What is the particle's velocity function v(t)v(t)?

A.v(t)=t2v(t)=t^2 m/s
B.v(t)=2t+1v(t)=2t+1 m/s
C.v(t)=t33+tv(t)=\dfrac{t^3}{3}+t m/s
D.v(t)=2tv(t)=2t m/s

Explanation

Core Concept

Velocity is the derivative of position. Differentiating gives s(t)=2ts'(t)=2t.

Correct Answer

Dv(t)=2tv(t)=2t m/s

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