AP Calculus ABeasymcq1 pt

A particle moves along a line with position s(t)=t24t+7s(t)=t^2-4t+7 meters at time tt seconds. At what time is the particle at rest?

A.t=0t=0 s
B.t=2t=2 s
C.t=1t=1 s
D.t=4t=4 s

Explanation

Core Concept

The particle is at rest when v(t)=0v(t)=0. Since v(t)=s(t)=2t4v(t)=s'(t)=2t-4, setting 2t4=02t-4=0 gives t=2t=2.

Correct Answer

Bt=2t=2 s

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