A particle moves along the $x$-axis so that its velocity at time $t \ge 0$ is given by $v(t) = t^2 - 5t + 6$. At time $t = 1.5$, is the speed of the particle increasing or decreasing, and why?

Question

Accepted Answer

A. Decreasing, because $v(1.5)$ is positive and $a(1.5)$ is negative.

Answer

Decreasing, because $v(1.5)$ is positive and $a(1.5)$ is negative.

Answer

Increasing, because $v(1.5)$ is positive and $a(1.5)$ is negative.

Answer

Decreasing, because $v(1.5)$ is negative and $a(1.5)$ is negative.

Answer

Increasing, because the absolute value of $v(t)$ is increasing for $t > 2.5$.

A particle moves along the $x$ -axis so that its velocity at time $t \ge 0$ is given by $v(t) = t^2 - 5t + 6$ . At time $t = 1.5$ , is the speed of the particle increasing or decreasing, and why?

Explanation

Core Concept

Correct Answer

More Unit 4: Contextual Applications of Differentiation practice questions

A particle moves along the xxx-axis so that its velocity at time t≥0t \ge 0t≥0 is given by v(t)=t2−5t+6v(t) = t^2 - 5t + 6v(t)=t2−5t+6. At time t=1.5t = 1.5t=1.5, is the speed of the particle increasing or decreasing, and why?

Explanation

Core Concept

Correct Answer

More Unit 4: Contextual Applications of Differentiation practice questions

A particle moves along the $x$ -axis so that its velocity at time $t \ge 0$ is given by $v(t) = t^2 - 5t + 6$ . At time $t = 1.5$ , is the speed of the particle increasing or decreasing, and why?