AP Chemistryeasymcq1 pt
How much heat is needed to raise 100.0 g of water from 20.0 °C to 30.0 °C? (c = 4.18 J/g·°C)
A.4.18 kJ
B.418 J
C.41.8 kJ
D.8.36 kJ
Explanation
Core Concept
q = mcΔT = 100.0 g × 4.18 J/g·°C × 10.0 °C = 4180 J = 4.18 kJ.
Correct Answer
A4.18 kJ
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