AP Chemistryhardmcq1 pt
What is the molality of a solution with 18.0 g of glucose (180 g/mol) in 500 g of water?
A.0.200 m
B.0.100 m
C.2.00 m
D.0.360 m
Explanation
Core Concept
Moles = 18.0 ÷ 180 = 0.100 mol; molality = 0.100 mol ÷ 0.500 kg = 0.200 m. Molality divides by kilograms of solvent.
Correct Answer
A0.200 m
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