AP Physics 1mediummcq1 pt
A 0.10 kg mass on a spring of k = 40 N/m is stretched 0.050 m and released from rest. Its speed at the equilibrium point is
A.1.0 m/s
B.2.0 m/s
C.0.50 m/s
D.20 m/s
Explanation
Core Concept
v = A√(k/m) = 0.050√(40/0.10) = 0.050(20) = 1.0 m/s.
Correct Answer
A1.0 m/s
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