AP Physics 1mediummcq1 pt
A mass m is attached to a spring with spring constant k. The spring is stretched a distance A from equilibrium and released. What is the maximum speed of the mass?
A.A√(k/m)
B.A√(m/k)
C.(1/2)A√(k/m)
D.(1/2)A√(m/k)
Explanation
Core Concept
The maximum speed occurs when the mass passes through the equilibrium position, where all the potential energy (1/2)kA² has been converted to kinetic energy (1/2)mvₘax². Setting these equal: (1/2)kA² = (1/2)mvₘax². Solving for vₘax: vₘax = A√(k/m).
Correct Answer
AA√(k/m)
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