AP Calculus ABeasymcq1 pt
A.
B.Does not exist
C.
D.
Explanation
Core Concept
As grows without bound, becomes arbitrarily close to , so the limit is .
Correct Answer
C
More Unit 1: Limits and Continuity practice questions
- hardLet $f(x)=\begin{cases} x^2+ax, & x<1 \\ bx+3, & x>1 \end{cases}$. If $f(1)=2$ and $f$ is continuous at $x=1$, what is $a+b$?
- hardSuppose $x^3\le f(x)\le x$ for all $x$ in $(0,1)$. What is $\lim_{x\to 0^+} f(x)$?
- hard$\lim_{x\to 0} x^2\sin\left(\frac{1}{x}\right)=$
- hardSuppose $f$ is continuous on $[0,3]$ with $f(0)=-4$ and $f(3)=1$. Which statement is guaranteed by the Intermediate Value Theorem?
- hardLet $f(x)=x^3-x-1$. Given that $f(1)=-1$ and $f(2)=5$, which interval is guaranteed to contain a zero of $f$ by the Intermediate Value Theor…
Practice more AP Calculus AB questions with full explanations
Practice Unit 1: Limits and Continuity Questions →