AP Calculus ABeasymcq1 pt

limx5x5x+3=\lim_{x\to 5}\dfrac{x-5}{x+3}=

A.11
B.00
C.55
D.Does not exist

Explanation

Core Concept

Direct substitution gives 555+3=08=0\frac{5-5}{5+3}=\frac{0}{8}=0. The numerator is zero while the denominator is nonzero.

Correct Answer

B00

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