Apentix/AP Calculus AB/Unit 1: Limits and Continuity/Question

AP Calculus ABmediummcq1 pt

$\lim_{x\to 0}\dfrac{\sin(3x)}{x}=$

A.

3

B.

1

C.

0

D.Does not exist

Explanation

Core Concept

Rewrite as $3\cdot\frac{\sin(3x)}{3x}$ . Since $\lim_{u\to 0}\frac{\sin u}{u}=1$ , the limit is $3\cdot 1=3$ .

Correct Answer

A $3$

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