AP Calculus ABmediummcq1 pt

limh0(3+h)29h=\lim_{h\to 0}\dfrac{(3+h)^2-9}{h}=

A.66
B.00
C.99
D.Does not exist

Explanation

Core Concept

Expand: (3+h)29=9+6h+h29=6h+h2(3+h)^2-9=9+6h+h^2-9=6h+h^2. Dividing by hh gives 6+h6+h, which approaches 66. This limit is the derivative of x2x^2 at x=3x=3.

Correct Answer

A66

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