AP Calculus ABmediummcq1 pt
Let g(x) = 1/(x - 3). What is the limit of g(x) as x approaches 3 from the left?
A.-∞: the values drop without bound
B.+∞: the values rise without bound
C.0
D.-3
Approaching 3 from the left keeps x - 3 negative and arbitrarily close to 0. The fraction 1/(x - 3) is therefore negative with magnitude growing without bound, so the left-hand limit is -∞ and x = 3 is a vertical asymptote of the graph.
A-∞: the values drop without bound
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