AP Calculus ABeasymcq1 pt

Let f(x)={x+1,x<2x2,x2f(x)=\begin{cases} x+1, & x<2 \\ x^2, & x\ge 2 \end{cases}. What is limx2f(x)\lim_{x\to 2^-} f(x)?

A.44
B.22
C.Does not exist
D.33

Explanation

Core Concept

For x<2x<2 the function is x+1x+1, so the left-hand limit is 2+1=32+1=3.

Correct Answer

D33

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