AP Chemistryhardmcq1 pt
The Ksp of PbI₂ is 9.8 × 10⁻⁹. What is the molar solubility?
A.1.3 × 10⁻³ M
B.9.9 × 10⁻⁵ M
C.2.1 × 10⁻³ M
D.4.9 × 10⁻⁹ M
For AB₂ salts: Ksp = 4s³, so s = (9.8 × 10⁻⁹ / 4)^(1/3) = (2.45 × 10⁻⁹)^(1/3) ≈ 1.3 × 10⁻³ M.
A1.3 × 10⁻³ M
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