AP Chemistryeasymcq1 pt
A 10.0 g iron nail (c = 0.45 J/g·°C) absorbs 90 J. What is its temperature rise?
A.20 °C
B.2.0 °C
C.200 °C
D.0.50 °C
Explanation
Core Concept
ΔT = q ÷ (m × c) = 90 ÷ (10.0 × 0.45) = 20 °C. Iron's low specific heat means modest energy moves its temperature a lot.
Correct Answer
A20 °C
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