AP Physics 2mediummcq1 pt
A hydraulic lift has a small piston of area 0.01 m² and a large piston of area 1 m². A force of 100 N is applied to the small piston. What force is exerted by the large piston?
A.1 N
B.100 N
C.1000 N
D.10000 N
Explanation
Core Concept
By Pascal's principle: F₁/A₁ = F₂/A₂. So F₂ = F₁ × A₂/A₁ = 100 × 1/0.01 = 10,000 N. The hydraulic lift multiplies force by the ratio of the areas.
Correct Answer
D10000 N
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