AP Physics 2mediummcq1 pt
A hydraulic lift has pistons of area 0.010 m² and 0.50 m². A 200 N force on the small piston lifts
A.10000 N
B.200 N
C.4.0 N
D.1000 N
Explanation
Core Concept
F₂ = F₁(A₂/A₁) = 200(0.50/0.010) = 10000 N.
Correct Answer
A10000 N
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