AP Physics 1hardmcq1 pt
A 5.0 kg hoop (I = mr², r = 0.40 m) rolls at 2.0 m/s. Its angular momentum about its center is
A.4.0 kg·m²/s
B.2.0 kg·m²/s
C.8.0 kg·m²/s
D.1.0 kg·m²/s
Explanation
Core Concept
ω = 5.0 rad/s; L = Iω = (5.0)(0.16)(5.0) = 4.0 kg·m²/s.
Correct Answer
A4.0 kg·m²/s
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