AP Chemistryhardmcq1 pt
For Cu²⁺ + 2e⁻ → Cu, what happens to the potential if [Cu²⁺] falls below 1 M?
A.It decreases
B.It increases
C.It stays at E°
D.It becomes zero
Explanation
Core Concept
Nernst: E = E° − (0.0592/2) log(1/[Cu²⁺]). Lower [Cu²⁺] makes Q > 1, so the correction subtracts and E drops.
Correct Answer
AIt decreases
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