AP Chemistrymediummcq1 pt
Given ΔH° = −100 kJ and ΔS° = −200 J/K, at which temperature is the reaction at equilibrium (ΔG° = 0)?
A.500 K
B.200 K
C.1000 K
D.2 K
Explanation
Core Concept
T = ΔH°/ΔS° = (−100,000 J)/(−200 J/K) = 500 K. Below 500 K the reaction is favored; above it, not.
Correct Answer
A500 K
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