AP Physics 1mediummcq1 pt
A force of 20 N is applied at an angle of 30° to a door 0.80 m from the hinge. The torque about the hinge is
A.8.0 N·m
B.16 N·m
C.4.0 N·m
D.14 N·m
τ = rF sinθ = (0.80)(20)(0.50) = 8.0 N·m.
A8.0 N·m
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