AP Chemistryhardmcq1 pt
A 2.00 L flask holds 4.0 g of He (4.0 g/mol) at 300 K. What pressure results? (R = 0.08206 L·atm/mol·K)
A.12.3 atm
B.24.6 atm
C.6.2 atm
D.0.41 atm
Explanation
Core Concept
n = 4.0 g ÷ 4.0 g/mol = 1.0 mol. P = nRT/V = (1.0 × 0.08206 × 300) ÷ 2.00 = 12.3 atm.
Correct Answer
A12.3 atm
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