AP Chemistryhardmcq1 pt
What is the pH of 0.10 M H₂SO₄ (first ionization complete, Ka2 = 1.0 × 10⁻²)?
A.0.97
B.1.00
C.0.70
D.7.00
The first proton gives 0.10 M H⁺. The second ionization adds x from Ka2 = (0.10 + x)(x)/(0.10 − x) = 0.010, giving x ≈ 0.008 M. Total [H⁺] ≈ 0.108 M, so pH ≈ 0.97.
A0.97
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