AP Chemistrymediummcq1 pt

Which expression correctly relates the standard cell potential to the equilibrium constant at 25 °C?

A.E°cell = (0.0592 V / n) log K
B.E°cell equals negative (0.0592 V / n) log K
C.E°cell = (n / 0.0592 V) log K
D.E°cell equals n times 96,485 times log K

Explanation

Core Concept

Combining ΔG° = −nFE°cell with ΔG° = −RT ln K and converting logarithms gives E°cell = (0.0592/n) log K at 298 K. A large, product-favored K forces a large positive E°, matching spontaneity. The form also shows why doubling an equation, which doubles n, leaves both E° and K unchanged.

Correct Answer

AE°cell = (0.0592 V / n) log K

More Unit 9: Applications of Thermodynamics practice questions

Try a random question →

Practice more AP Chemistry questions with full explanations

Practice Unit 9: Applications of Thermodynamics Questions →