AP Chemistryhardmcq1 pt
Estimate ΔH for CH₄ + Cl₂ → CH₃Cl + HCl using bond enthalpies: C–H 413, Cl–Cl 243, C–Cl 328, H–Cl 431 kJ/mol.
A.−103 kJ
B.+103 kJ
C.−431 kJ
D.+656 kJ
Explanation
Core Concept
Broken: one C–H (413) + one Cl–Cl (243) = 656. Formed: one C–Cl (328) + one H–Cl (431) = 759. ΔH = 656 − 759 = −103 kJ.
Correct Answer
A−103 kJ
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