AP Chemistryhardmcq1 pt
What is the equilibrium constant K for a reaction with ΔG° = −11.4 kJ at 298 K?
A.100
B.10
C.1000
D.0.01
Explanation
Core Concept
ln K = −ΔG°/RT = 11,400 ÷ (8.314 × 298) = 4.60, so K = e⁴.60 ≈ 100. Each −5.7 kJ of ΔG° at 298 K multiplies K by 10.
Correct Answer
A100
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