AP Physics 2mediummcq1 pt
An electron jumps from −3.4 eV to −13.6 eV. The emitted photon's energy is
A.10.2 eV
B.17.0 eV
C.3.4 eV
D.13.6 eV
E = (−3.4) − (−13.6) = 10.2 eV.
A10.2 eV
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