AP Physics 1hardmcq1 pt
A 60 kg diver falls 10 m into water and stops in 0.50 s. The average force the water exerts is about (g = 10 m/s²)
A.4600 N
B.2300 N
C.1200 N
D.600 N
Impact speed is √(2gh) ≈ 14.1 m/s. The water stops the diver, so the average net force plus the diver's weight gives F ≈ mΔv/Δt + mg ≈ (60)(14.1)/0.5 + 600 ≈ 2290 N.
B2300 N
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