AP Calculus ABmediummcq1 pt

What is limx0ex1x\displaystyle\lim_{x\to 0}\dfrac{e^x-1}{x}?

A.00
B.11
C.ee
D.does not exist

Explanation

Core Concept

The form is 00\dfrac{0}{0}, so L'Hôpital's rule applies. Differentiating gives ex1\dfrac{e^x}{1}, which approaches e0=1e^0=1.

Correct Answer

B11

More Unit 4: Contextual Applications of Differentiation practice questions

Try a random question →

Practice more AP Calculus AB questions with full explanations

Practice Unit 4: Contextual Applications of Differentiation Questions →