AP Chemistrymediummcq1 pt
A 10.0 L container holds 0.500 mol of gas at 27 °C. What is the pressure? (R = 0.08206 L·atm/mol·K)
A.1.23 atm
B.0.123 atm
C.12.3 atm
D.2.46 atm
Explanation
Core Concept
Convert to Kelvin: 27 + 273 = 300 K. P = nRT/V = (0.500 × 0.08206 × 300) ÷ 10.0 = 1.23 atm.
Correct Answer
A1.23 atm
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