AP Chemistrymediummcq1 pt
A compound is 40.0% carbon, 6.7% hydrogen, and 53.3% oxygen by mass. What is its empirical formula?
A.CH₂O
B.C₂H₄O
C.CHO
D.C₂H₆O
Assume 100 g: C 40.0/12.01 = 3.33 mol, H 6.7/1.008 = 6.65 mol, O 53.3/16.00 = 3.33 mol. Divide by 3.33 to get C:H:O = 1:2:1, so CH₂O.
ACH₂O
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