AP Physics 2mediummcq1 pt
A +2.0 µC charge moves through a potential difference of 50 V. Its potential energy change is
A.1.0×10⁻⁴ J
B.1.0×10⁻⁵ J
C.1.0×10⁻³ J
D.2.5×10⁻⁵ J
Explanation
Core Concept
ΔU = qΔV = (2.0×10⁻⁶)(50) = 1.0×10⁻⁴ J.
Correct Answer
A1.0×10⁻⁴ J
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