AP Chemistrymediummcq1 pt
What is E°cell for a cell with Zn anode and Cu cathode? (E° Zn²⁺/Zn = −0.76 V; Cu²⁺/Cu = +0.34 V)
A.1.10 V
B.−1.10 V
C.0.42 V
D.1.52 V
E°cell = E°cathode − E°anode = 0.34 − (−0.76) = 1.10 V. The spontaneous direction pairs the higher potential as cathode.
A1.10 V
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