AP Physics 2hardmcq1 pt
A 2.0 µF capacitor is charged to 100 V. The stored energy is
A.0.010 J
B.0.020 J
C.0.0050 J
D.1.0 J
Explanation
Core Concept
U = ½CV² = ½(2.0×10⁻⁶)(10⁴) = 0.010 J.
Correct Answer
A0.010 J
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