AP Physics 2mediummcq1 pt
A 9.0 V battery with internal resistance 1.0 Ω is shorted by a wire of negligible resistance. The short-circuit current is
A.9.0 A
B.1.0 A
C.0.11 A
D.18 A
Explanation
Core Concept
I = ε/r = 9.0/1.0 = 9.0 A.
Correct Answer
A9.0 A
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