AP Physics 2mediummcq1 pt
A 9.0 V battery has internal resistance 0.50 Ω and drives 2.0 A. Its terminal voltage is
A.8.0 V
B.9.0 V
C.10 V
D.7.0 V
Explanation
Core Concept
V_terminal = ε − Ir = 9.0 − (2.0)(0.50) = 8.0 V.
Correct Answer
A8.0 V
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