AP Physics 1hardmcq1 pt
A 0.30 kg ball is thrown at 5.0 m/s and caught 0.40 m from the pivot of a frictionless rod system. The angular momentum transferred about the pivot is
A.0.60 kg·m²/s
B.1.5 kg·m²/s
C.0.30 kg·m²/s
D.2.0 kg·m²/s
Explanation
Core Concept
L = mvr = (0.30)(5.0)(0.40) = 0.60 kg·m²/s.
Correct Answer
A0.60 kg·m²/s
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