AP Physics 2mediummcq1 pt
A converging lens with a focal length of 20 cm is used to form an image of an object placed 30 cm from the lens. What is the magnification of the image?
A.B) 0.5
B.A) -0.5
C.C) -1.5
D.D) 1.5
Using the lens equation 1/f = 1/do + 1/di, where f = 20 cm and do = 30 cm, we get 1/di = 1/20 - 1/30 = 0.05 - 0.033 = 0.017. Therefore, di = 1/0.017 = 60 cm. The magnification is m = -di/do = -60/30 = -1.5. The negative sign indicates an inverted image, but the magnitude is 1.5.
DD) 1.5
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