AP Physics 2easymcq1 pt

A rectangular loop of wire with dimensions 0.20 m × 0.30 m is placed in a uniform magnetic field of 0.50 T. The normal to the loop makes an angle of 30° with the magnetic field. What is the magnetic flux through the loop?

A.B) 0.030 Wb
B.D) 0.120 Wb
C.A) 0.026 Wb
D.C) 0.060 Wb

Explanation

Core Concept

Magnetic flux is given by Φ = BA cosθ, where B is the magnetic field strength, A is the area of the loop, and θ is the angle between the magnetic field and the normal to the loop. The area A = (0.20 m)(0.30 m) = 0.06 m². Therefore, Φ = (0.50 T)(0.06 m²)cos(30°) = 0.026 Wb.

Correct Answer

CA) 0.026 Wb

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