AP Physics 2mediummcq1 pt
Three resistors of 6Ω, 3Ω, and 2Ω are connected in parallel. What is the equivalent resistance of this combination?
A.B) 1.0 Ω
B.A) 11 Ω
C.C) 6 Ω
D.D) 1.5 Ω
Explanation
Core Concept
For resistors in parallel, the equivalent resistance is calculated as 1/R_eq = 1/R1 + 1/R2 + 1/R3. Substituting the values: 1/R_eq = 1/6 + 1/3 + 1/2 = 1/6 + 2/6 + 3/6 = 6/6 = 1. Therefore, R_eq = 1.0 Ω.
Correct Answer
AB) 1.0 Ω
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