A charged particle is moving in a uniform magnetic field perpendicular to its velocity. If the particle's speed is doubled, how does this affect the radius of its circular path?

Core Concept

When a charged particle moves perpendicular to a uniform magnetic field, it follows a circular path with radius r = mv/(qB), where m is mass, v is speed, q is charge, and B is magnetic field strength. If the speed v is doubled, the radius r also doubles, assuming all other factors remain constant.