AP Physics 2hardmcq1 pt

An ideal gas undergoes an isothermal expansion at 300 K. During this process, the gas does 500 J of work on the surroundings. What is the change in internal energy of the gas and the heat transferred to the gas?

A.C) ΔU = 500 J, Q = 0 J
B.D) ΔU = 500 J, Q = 500 J
C.A) ΔU = 0 J, Q = 0 J
D.B) ΔU = 0 J, Q = 500 J

Explanation

Core Concept

For an ideal gas, the internal energy depends only on temperature. Since the process is isothermal (constant temperature), ΔU = 0 J. From the first law of thermodynamics, ΔU = Q - W, where Q is heat added to the system and W is work done by the system. Rearranging, Q = ΔU + W = 0 J + 500 J = 500 J.

Correct Answer

DB) ΔU = 0 J, Q = 500 J

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