AP Physics 1mediummcq1 pt

A mass m is attached to a spring with spring constant k. The spring is stretched a distance A from equilibrium and released. What is the maximum speed of the mass?

A.A) A√(k/m)

B.B) A√(m/k)

C.C) (1/2)A√(k/m)

D.D) (1/2)A√(m/k)

Explanation

Core Concept

The maximum speed occurs when the mass passes through the equilibrium position, where all the potential energy (1/2)kA² has been converted to kinetic energy (1/2)mv_max². Setting these equal: (1/2)kA² = (1/2)mv_max². Solving for v_max: v_max = A√(k/m).

Correct Answer

AA) A√(k/m)

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